A man throws a ball to maximum horizontal distance of 80 m. Calculate the maximum height reached.
A man throws a ball to maximum horizontal distance of 80 m. Calculate the maximum height reached.
Utkarsh , 11 Years ago
Grade
Mechanics> A man throws a ball to maximum horizontal...
3 Answers
rahul
20metres
Shivam Chopra
We know that R = u2 * Sin 2θ / g.
As, the range is maximum, so, θ = 450
So, 80 = u2 /g.
Now, H = height reached by ball = u2 Sin2θ / 2g.
Putting value of θ = 450 , u2 / g = 80, we get
H = 80/4 = 20m
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Approved Last Activity: 11 Years ago
Hassnain Ali
A we know that Range is n times the Height of Projectile.
R=4H
As the maximum distance is 80m which is no doubt equal to 80m.So Putting values
80m=4H
80/4=H
20=H
So maximum height is 20m
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