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A man throws a ball to maximum horizon talk distance of 80meters. Calcurate the maximum height reached

A man throws a ball to maximum horizon talk distance of 80meters. Calcurate the maximum height reached
 

Grade:

2 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
4 years ago
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Vikas TU
14149 Points
4 years ago
Dear student 
Max range is for angle 45
80 = u^2 Sin^2(x)/g
Solve for u , you will get.
u = 40
max height=u^2 Sin^2(x)/2g 
h=80/2m=40m

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