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Grade:
        
A man throws a ball to maximum horizon talk distance of 80meters. Calcurate the maximum height reached
 
one month ago

Answers : (2)

Saurabh Koranglekar
askIITians Faculty
2961 Points
							576-998_156621564870668857124.jpg
						
one month ago
Vikas TU
8478 Points
							
Dear student 
Max range is for angle 45
80 = u^2 Sin^2(x)/g
Solve for u , you will get.
u = 40
max height=u^2 Sin^2(x)/2g 
h=80/2m=40m
one month ago
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