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Grade 12Mechanics

A man start running from rest on a plank with maximum possible acceleration from point A
(1)Plank remains stationary during motion
(2)Man takes 2s to move from A to B
(3)Velocity of man w.r.t ground is 8m/s when he reaches at point B
(4)Acceleration of plank is 0.5 ms-2 during motion of man

Question image for A man start running from rest on a plank with max
Profile image of Hirthick Kumaran
8 Years agoGrade 12
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1 Answer

Profile image of Askiitians Tutor Team
ApprovedApproved Tutor Answer11 Months ago

To analyze the scenario where a man runs on a plank while the plank itself accelerates, we can break down the problem into manageable parts. We need to consider the motion of both the man and the plank, applying the principles of physics, particularly Newton's laws of motion.

Understanding the Motion

We have a man who starts from rest and runs on a plank that is accelerating. The key points to note are:

  • The plank remains stationary initially but starts to accelerate.
  • The man takes 2 seconds to move from point A to point B.
  • His final velocity with respect to the ground when he reaches point B is 8 m/s.
  • The acceleration of the plank is 0.5 m/s² during this time.

Analyzing the Man's Motion

Since the man starts from rest, we can use the equations of motion to describe his movement. The final velocity (v) of the man is given as 8 m/s, and he takes 2 seconds (t) to reach this velocity. We can use the formula:

v = u + at

Here, u is the initial velocity (0 m/s since he starts from rest), a is the acceleration of the man, and t is the time (2 seconds). Rearranging the formula gives us:

a = (v - u) / t

Substituting the known values:

a = (8 m/s - 0 m/s) / 2 s = 4 m/s²

Considering the Plank's Motion

While the man accelerates, the plank also accelerates at 0.5 m/s². To find the distance covered by the man relative to the ground, we can use the equation:

s = ut + (1/2)at²

For the man, substituting the values gives:

s = 0 + (1/2)(4 m/s²)(2 s)² = 8 m

This means the man covers 8 meters relative to the ground. However, we also need to consider the distance the plank moves during this time.

Distance Covered by the Plank

Using the same formula for the plank, where its initial velocity is 0 and its acceleration is 0.5 m/s²:

s_plank = ut + (1/2)at²

Substituting the values for the plank:

s_plank = 0 + (1/2)(0.5 m/s²)(2 s)² = 1 m

Final Analysis

Now, we can summarize the findings:

  • The man runs 8 meters relative to the ground.
  • The plank moves 1 meter during the same time.

Thus, the distance the man covers relative to the plank is:

Distance relative to plank = Distance covered by man - Distance covered by plank

Distance = 8 m - 1 m = 7 m

In conclusion, the man effectively runs 7 meters relative to the plank while the plank itself moves 1 meter. This scenario beautifully illustrates the interplay between two objects in motion, showcasing how their respective accelerations and velocities can be analyzed using fundamental physics principles.