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A man stands on a frictionless platform that is rotating with an angular speed of 1.22 rev/s; his arms are outstretched and he holds a weight in each hand. With his hands in this position the total rotational inertia of the man, the weights, and the platform is 6.13 kg' m 2 If by moving the weights the man decreases the rotational inertia to 1.97 kg' m 2 , what is the resulting angular speed of the platform?

A man stands on a frictionless platform that is rotating with an angular speed of 1.22 rev/s; his arms are outstretched and he holds a weight in each hand. With his hands in this position the total rotational inertia of the man, the weights, and the platform is 6.13 kg' m2 If by moving the weights the man decreases the rotational inertia to 1.97 kg' m2, what is the resulting angular speed of the platform?

Grade:upto college level

1 Answers

Navjyot Kalra
askIITians Faculty 654 Points
8 years ago
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