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Grade: upto college level
        
A man stands on a frictionless platform that is rotating with an angular speed of 1.22 rev/s; his arms are outstretched and he holds a weight in each hand. With his hands in this position the total rotational inertia of the man, the weights, and the platform is 6.13 kg' m2 If by moving the weights the man decreases the rotational inertia to 1.97 kg' m2, what is the resulting angular speed of the platform?
5 years ago

Answers : (1)

Navjyot Kalra
askIITians Faculty
654 Points
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5 years ago
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Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


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