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`        A man pushes a cylinder of mass m1 and with help of plank m2 there is no slipping as in figure in attachment horizontal force is F    1)acc of cm of cylinder is?2)F riction between plank and cylinder 3)`
4 months ago

Arun
23492 Points
```							- Now draw the FBD of two bodies. The cylinder in the bottom will have the following set of forces  f1=force of friction between the two bodies and is towards right for the cylinder and towards left for the plank.  f2=force of friction between the ground and the cylinder and is towards left. F=applied horizontal force on the plank a1= Acceleration of the plank towards the right a= Acc of the cylinder towards right ß= Angular Acc of the cylinder Then the eqns of motion are F-f1=M2 a1.........................(1) f1 - f2=M1 a........................(2) (f1+f2)r=Iβ...........................(3) (where I= momont of inertia= 1/2 M2 r²) And the conditions of non slleeping are a1=a+ βr..................(4)(At the top cotact of two bodies) a2=βr..............(5)(At the contact of the cylinder and the ground) Solving these Eqsns we get a=4F/(8M2+3M1) a1=8F/(8M2+3M1)
```
4 months ago
Vikas TU
10041 Points
```							Dear student Please follow the followuing Link for correct explanationhttps://www.askiitians.com/forums/Mechanics/10/9558/rotational.htmHope this helps Good Luck
```
4 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions