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A man pushes a cylinder of mass m1 and with help of plank m2 there is no slipping as in figure in attachment horizontal force is F    
1)acc of cm of cylinder is?
2)F riction between plank and cylinder 
3)
2 months ago

Answers : (2)

Arun
23049 Points
							
- Now draw the FBD of two bodies.
 
The cylinder in the bottom will have the following set of forces 
 
f1=force of friction between the two bodies and is towards right for the cylinder and towards left for the plank. 
 
f2=force of friction between the ground and the cylinder and is towards left.
 
F=applied horizontal force on the plank
 
a1= Acceleration of the plank towards the right
 
a= Acc of the cylinder towards right
 
ß= Angular Acc of the cylinder
 
Then the eqns of motion are
 
F-f1=M2 a1.........................(1)
 
f1 - f2=M1 a........................(2)
 
(f1+f2)r=Iβ...........................(3) (where I= momont of inertia= 1/2 M2 r²)
 
And the conditions of non slleeping are
 
a1=a+ βr..................(4)(At the top cotact of two bodies)
 
a2=βr..............(5)(At the contact of the cylinder and the ground)
 
Solving these Eqsns we get
 
a=4F/(8M2+3M1)
 
a1=8F/(8M2+3M1)
2 months ago
Vikas TU
9517 Points
							
Dear student 
Please follow the followuing Link for correct explanation
Hope this helps 
Good Luck 
2 months ago
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