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Grade 12Mechanics

A man of mass m slides down along a rope which is connected to the ceilling of an elevatorwith decclaration’a’ relative to the rope.If the elevator is going upwards with an accelration a relative to the ground then tension in the rope is.....

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7 Years agoGrade 12
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ApprovedApproved Tutor Answer1 Year ago

To determine the tension in the rope when a man of mass \( m \) is sliding down, we need to analyze the forces acting on him in relation to the elevator's motion. The situation involves both the man's acceleration relative to the rope and the elevator's upward acceleration. Let's break this down step by step.

Understanding the Forces at Play

When the man slides down the rope, two main forces act on him:

  • The gravitational force acting downward, which is \( mg \) (where \( g \) is the acceleration due to gravity).
  • The tension in the rope, which acts upward.

Since the elevator is accelerating upwards with an acceleration \( a \), we need to consider this when analyzing the man's motion. The effective acceleration acting on the man becomes \( g + a \) because the upward acceleration of the elevator adds to the gravitational pull he experiences.

Setting Up the Equation

Using Newton's second law, we can express the net force acting on the man as follows:

The net force \( F_{\text{net}} \) acting on the man can be expressed as:

\( F_{\text{net}} = T - mg \)

where \( T \) is the tension in the rope. Since the man is accelerating downwards relative to the rope with an acceleration \( a \), we can also express the net force in terms of mass and acceleration:

\( F_{\text{net}} = ma \)

Combining the Equations

Now we can set the two expressions for \( F_{\text{net}} \) equal to each other:

\( T - mg = -ma \)

Here, the negative sign indicates that the acceleration \( a \) is in the opposite direction to the tension. Rearranging this equation gives us:

\( T = mg - ma \)

Final Expression for Tension

Now, we can factor out \( m \) from the right side:

\( T = m(g - a) \)

This equation tells us that the tension in the rope depends on the mass of the man, the acceleration due to gravity, and the upward acceleration of the elevator. If the elevator's acceleration \( a \) is less than \( g \), the tension will be positive, indicating that the rope is indeed under tension. If \( a \) were to equal \( g \), the tension would be zero, meaning the man would be in free fall relative to the elevator.

Example Calculation

Let’s say the mass of the man \( m \) is 70 kg, the acceleration due to gravity \( g \) is approximately 9.81 m/s², and the elevator's upward acceleration \( a \) is 2 m/s². Plugging these values into our tension formula:

\( T = 70(9.81 - 2) \)

Calculating this gives:

\( T = 70 \times 7.81 = 546.7 \, \text{N} \)

This means the tension in the rope while the man is sliding down the rope in an upward-accelerating elevator is approximately 546.7 N.

In summary, the tension in the rope is influenced by both the gravitational force and the upward acceleration of the elevator, leading to the final expression \( T = m(g - a) \). This relationship is crucial for understanding dynamics in non-inertial reference frames, such as an accelerating elevator.