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A man of mass 83 kg (weight 180 lb) jumps down to a concrete patio from a window ledge only 0.48 m (= 1.6 ft) above the ground. He neglects to bend his knees on landing, so that his motion is arrested in a distance of about 2.2 cm (= 0.87 in.). (a) What is the average acceleration of the man from the time his feet first touch the patio to the time he is brought fully to rest? (b) With what average force does this jump jar his bone structure?
A man of mass 83 kg (weight 180 lb) jumps down to a concrete patio from a window ledge only 0.48 m (= 1.6 ft) above the ground. He neglects to bend his knees on landing, so that his motion is arrested in a distance of about 2.2 cm (= 0.87 in.). (a) What is the average acceleration  of the man from the time his feet first touch the  patio to the time he is brought fully to rest? (b) With what average force does this jump jar his bone structure?

```
5 years ago

Abhinav
387 Points
```							for first part2gh=-2ada = -gh/dif we use g=10 m/s2a= – 4.8*100 /2.2 = -218.18 m/s2andhence ,average force on man is = a*m
```
5 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions