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A man of mass 60 kg is standing on a light weighing machine kept in a box of mass 30 kg. The box is hanging from a pulley fixed to athe ceiling through a light rope the other end of which is held by the man himself .if the manages to keep the box at restwhat is the weight shown in the machie ? what force should he exert on the rope to get his correct weight on the machine ??

Jitender Pal , 12 Years ago
Grade 9
anser 1 Answers
Askiitians Tutor Team

To solve this problem, we need to analyze the forces acting on the man and the box. The scenario involves a man standing on a weighing machine inside a box that is suspended from a pulley. The man is holding the rope attached to the box, and he is trying to keep the box at rest. Let's break this down step by step.

Understanding the Forces at Play

First, we need to identify the forces acting on both the man and the box:

  • The weight of the man (Wman) is given by the formula: Wman = mass × gravity = 60 kg × 9.81 m/s² = 588.6 N.
  • The weight of the box (Wbox) is: Wbox = 30 kg × 9.81 m/s² = 294.3 N.

Analyzing the Situation

When the man pulls on the rope, he exerts a force that affects both his weight reading on the machine and the tension in the rope. If the box is at rest, the forces acting on it must be balanced. The tension (T) in the rope must equal the weight of the box:

T = Wbox = 294.3 N.

Weight Shown on the Machine

The weighing machine measures the normal force (N) exerted by the man on the machine. When the man pulls on the rope, he is effectively reducing the force that he exerts on the machine. The normal force can be expressed as:

N = Wman - T.

Substituting the values we calculated:

N = 588.6 N - 294.3 N = 294.3 N.

Thus, the weight shown on the machine is 294.3 N.

Force Required to Maintain Correct Weight

If the man wants the weighing machine to show his actual weight (588.6 N), he needs to exert a force on the rope that compensates for the weight of the box. In this case, he would need to exert a force equal to the weight of the box:

Force exerted (F) = Wbox = 294.3 N.

By pulling with this force, the tension in the rope will equal the weight of the box, and the normal force on the weighing machine will equal his actual weight.

Summary of Findings

In summary, when the man keeps the box at rest, the weighing machine shows a weight of 294.3 N. To have the machine display his correct weight of 588.6 N, he must exert a force of 294.3 N on the rope. This balance of forces is crucial in understanding how tension and weight interact in this system.

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