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Grade 12Mechanics

A man of 50 kg is standing in a gravity free space at height of 10m above the floor.he threw a stone of 0.5kg mass downward with speed 2m/s.distance between man and above the floor

Profile image of aditi verma
10 Years agoGrade 12
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1 Answer

Profile image of Arnav Prasad
10 Years ago
I hope you framed the question right, it must be distance of man from floor when the ball hits the floor...
 
Apply concept of centre of mass, since there is no Gravity in the space, centre of mass will remain stationary.
 
X being the position,
Xcom = 0 = (MmanXman + MstoneXstone) / (Mstone + Mman) .
 
Xman = –  MstoneXstone/Mman .
Xman = – 0.5(10)/50 = – 0.1 metre.
 
When stone reaches 10 metres down, man moves 0.1 metres up with respect to inital position.
Thus, distance between man and floor is 10.1 metres.