A man moves on a straight horizontal road with a block in his hand . If he covers a distance of 40m with an acceleration of 0.5ms^-2. find the work done during the motion

Question

Shailendra Kumar Sharma · Answer

assume the mass of block be m
so work done can be calculated W =change in kinetic energy =K2-K1
the velocity after covering 40m
V²=u²+2aS

So V2 =40
Now kinetic energy will be (1/2)mV2 =20m
So the work done will be 20mJ

Gurmeet · Answer

Let suppose a block of mass m so work energy theoryWork done=change in kinetic energy =K2-K1the velocity attined after covering 40m V2=u2+2aSSo V2 =40Now change in kinetic energy will be (1/2)mV2 =20mSo the work done will be 20mJ using above equations

Sonam Tyagi · Answer

Given that a = 0.5 ms^2 m = 2 kg s = 40 m Now to find v^2 we use v^2= u^2 + 2as v= √40 Since by work energy therom Work done=∆ K.E. W= 40J

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A man moves on a straight horizontal road with a block in his hand . If he covers a distance of 40m with an acceleration of 0.5ms^-2. find the work done during the motion

A man moves on a straight horizontal road with a block in his hand . If he covers a distance of 40m with an acceleration of 0.5ms^-2. find the work done during the motion

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