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Grade 12Mechanics

A man is standing on a rough (cofficient of friction=0.5) horizontal disc rotating with angular velocity 5rad/sec. At what distance from centre should he stand so that he does not slip on the disc?

Profile image of atharv dixit
11 Years agoGrade 12
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2 Answers

Profile image of Mallikarjun Maram
11 Years ago
Here, friction provides required centripetal force to keep the man rotating without slipping. For safe rotation without slipping centripetal force should be less than maximum possible friction. At the upper limit mrω2 = μmg with the symbols having usual meanings. Hence rmax = μg/ω2. Substituting the values, we get rmax = 0.2 m.
Profile image of Mallikarjun Maram
11 Years ago
Here, friction provides required centripetal force to keep the man rotating without slipping. For safe rotation without slipping centripetal force should be less than maximum possible friction. At the upper limit mrω2 = μmg with the symbols having usual meanings. Hence rmax = μg/ω2. Substituting the values, we get rmax = 0.2 m.

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