A man is holding a rope which passes through a smooth pulley which then attached to a counter weight of same mass that of man. At initial both are at rest then the man starts climbing up with a acceleration of 2ms‐² find the time after which the man reaches the pulley

Question

Vikas TU · Answer

Dear student The ans is already explained , This is the solution: As monkey moving upwards So net force T-mg=3mg/2 (1) Also the block of mass 2m will move upwards as monkey pulls the rope while climbing therefore for block Net force T-2mg=ma (2) Substituting the value of T in (2) you get a=g/2 Hope this helps Good Luck

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A man is holding a rope which passes through a smooth pulley which then attached to a counter weight of same mass that of man. At initial both are at rest then the man starts climbing up with a acceleration of 2ms‐² find the time after which the man reaches the pulley

A man is holding a rope which passes through a smooth pulley which then attached to a counter weight of same mass that of man. At initial both are at rest then the man starts climbing up with a acceleration of 2ms‐² find the time after which the man reaches the pulley

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A man is holding a rope which passes through a smooth pulley which then attached to a counter weight of same mass that of man. At initial both are at rest then the man starts climbing up with a acceleration of 2ms‐² find the time after which the man reaches the pulley

A man is holding a rope which passes through a smooth pulley which then attached to a counter weight of same mass that of man. At initial both are at rest then the man starts climbing up with a acceleration of 2ms‐² find the time after which the man reaches the pulley

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