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A man in a balloon rising with constant velocity of 6 m/s propels a ball upwards with a velocity of 9 m/s, relative to the balloon. After what time interval will be the bal return to the balloon g-=9.8 m/s?
A man in a balloon rising with constant velocity of 6 m/s propels a ball upwards with a velocity of 9 m/s, relative to the balloon. After what time interval will be the bal return to the balloon g-=9.8 m/s?

```
2 years ago

Arun
25768 Points
```							Speed of balloon w.r.t ground=6 m/s (Upwards)Speed of stone w.r.t balloon=9 m/sSo, speed of stone w.r.t ground=6 +9=15 m/s​u=15 m/s (upwards)Using relationv=u+gt=15-10 x t = 0 t = 15/10 = 1.5 sec
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions