×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
A man crosses triver perpendicular to river flow in time ‘t’ seconds & travels an equal distance down the stream in ‘T’ seconds.The ratio of man’s speed in still water to the speed of river will be?

```
4 years ago

Rishabh singh
36 Points
```							Let velocity of man in stillbwater be v, and  water speed w.r. t observer in ground be u, So, velocity of man perpendicular moving will be =rootvover v^2-u^2 And velocity of downstream = v+uAcc. To. Que(Rootover v^2-u^2)t= (v+u) T         Then v/u comes out to be = t^2+T^2\t^2-T^2
```
3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions