×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
A man can swim at a speed of 3km/hr in still water;he wants to cross a 500m wide river flowing at 2km/hr.He keeps himself always at an angle of 120 with the river flow while swimming.Find the time he will take to cross the river.At what point on the opposite bank will he arrive?

```
3 years ago

Arun
25768 Points
```							Sum the horizontal components: 3*cos120 + 2 = -1.5 + 2 = 0.5km/h His vertical component = 3sin120 = 2.6km/h 0.500km/2.6 =0.1925hr = 11.6min 0.5*0.1925 = 0.0962km = 96.2m down stream What angle should he swim if he doesn't want to arrive downstream? 3cosx +2 = 0 -----> cosx = -2/3 -----> x = 131.8 degrees How long would it take to cross then? 13.4min What if he swam at 90 degrees to the current? 0.5/3 *60 = 10min but he would be 333m downstream
```
3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions