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Mechanics

A loose nut from a Bolt on the bottom of an elevator which is moving up the shaft at 3m/s falls freely.The nut strikes the bottom of the shaft in 2 second.Distance of the elevator from the bottom of the shaft when the net fell off is

Profile image of kahkashan sarfaraz
7 Years agoGrade
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1 Answer

Profile image of Eshan
7 Years ago
Dear student

The nut intially has the velocity of the elevator

\implies v_0=3m/s

The time taken to hit the bottom is 2s.
So uses=ut-\dfrac{1}{2}gt^2to obtain s=13.6m