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Mechanics

A liquid X of density 3.36 g/cm3 is poured in a U-tube, which contains Hg. Another liquid Y is poured in left arm with height 8 cm, upper levels of X and Y are same. What is density of Y?a. 0.8 9/00 b. 1.2 g/cc c. 1.4 9/00 d. 1.6 9/00

Sarthak Khandelwal

8 Years agoGrade

6 Answers

Arun

Approved Tutor Answer8 Years ago

Dear Sarthak

Hx * $\rho$ x * g = Hy * $\large \rho$ y * g + Hhg * $\large \rho$ hg * g

10 * 3.36 = 8 * $\large \rho$ y + 2 * 13.6

$\large \rho$ y = 0.8 gm/cm³

Regards

Arun (askIITiams forum expert)

Saurav

Approved Tutor Answer8 Years ago

actually the questio is incomplete!

but. i googled it and found the complete question

the height of X should also be given

it is 10cm there

now balance the pressur below 10cm from the top in both limbs of the u tube

you will get the following equation

d= density

d_x * g * H_x= d_y * g * H_y + d_mercury * g * H_mercury

_{as we are equating pressure below 10 cm from the top}

_{8cm will be of y and 2 cm of mercury in left limb}

_thereforeH_mercury = 2cm

also d_mercury=13.6 gm/cm³

3.36 * 10 = d_y * 8 + 13.6*2

d_y=0.8 gm/cm³

I WONDER HOW ARUN SOLVED IT WITHOUT H_X!!!!!!!!!!!!!

Arun

8 Years ago

Dear Saurav

I also thought the same as you have thought.

I solved it on my experience. I know that some thong is missing but can't reject by saying it incomplete question.

User

7 Years ago

height of X should also be given

it is 10cm there

now balance the pressur below 10cm from the top in both limbs of the u tube

you will get the following equation

d= density

d_x * g * H_x= d_y * g * H_y + d_mercury * g * H_mercury

_{as we are equating pressure below 10 cm from the top}

_{8cm will be of y and 2 cm of mercury in left limb}

_thereforeH_mercury = 2cm

also d_mercury=13.6 gm/cm³

3.36 * 10 = d_y * 8 + 13.6*2

d_y=0.8 gm/cm³

^{Hence option A}

Rishi Sharma

5 Years ago

Dear Student,
After reading the complete question and missing data from the comments.
Please find below the solution to your problem.

Density of liquid X-3.36g/ml
Density of liquid Y-dy
Density of mercury - 13.6
height of liquid X is 10 cm
height of liquid y is 8cm
Hy. Dy. g= hx. dx. g +HmDmg
Dy=60.8/8
=0.77=0.8

Thanks and Regards

Anuj Jain

4 Years ago

namaste’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’’to all

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