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        A liquid is kept in a  vessel of cylindrical size which is rotating along its axis. The liquid rises at the sides. If the radius of the vessel is 0.05m and the speed of rotaion is 2 rev/second , find the difference in height of the liquid at the centre of the vessel and its side g=9.8 m/s2
2 years ago

Arun
23325 Points
							Please find below the solution to your asked query.according to the bernoulli's theorem:p+12ρv2 = constantwe knoe v = rωapplying these equation at the side wall and centre of the vesselpcentre 12ρvcentre2 =  pside 12ρvside2 vcenter = 0pcentre −pside = 12ρr2ω2hρg =12ρr2ω2h = 12gr2ω2  = 1×0.05×0.05×(2π×2)220 = 0.02 m= 2 cm

2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions