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A liquid flows through a horizontal pipe whose inner radius is 5.35 cm. The pipe bends upward through a height of 9.8 m where it widens and joins another horizontal pipe of inner radius 6.8 cm. What must the volume flux be if the pressure in the two horizontal pipes is the same

Areeba khan , 5 Years ago
Grade 12th pass
anser 1 Answers
Askiitians Tutor Team

To determine the volume flux of the liquid flowing through the horizontal pipes, we can apply the principle of conservation of mass, specifically the continuity equation. This principle states that for an incompressible fluid, the mass flow rate must remain constant throughout the flow. In simpler terms, if the fluid is flowing through pipes of different diameters, the product of the cross-sectional area and the velocity of the fluid must be the same at any two points along the flow path.

Understanding the Problem

We have two sections of a pipe: the first section has an inner radius of 5.35 cm, and the second section has an inner radius of 6.8 cm. The pipe bends upward, but since we are told that the pressure in the two horizontal pipes is the same, we can ignore the effects of elevation change on pressure for this calculation. Our goal is to find the volume flux, which is the volume of fluid that passes through a given cross-section of the pipe per unit time.

Key Concepts

  • Continuity Equation: A1 * V1 = A2 * V2
  • Volume Flux (Q): Q = A * V, where A is the cross-sectional area and V is the fluid velocity.

Calculating Cross-Sectional Areas

First, we need to calculate the cross-sectional areas of both pipes. The area (A) of a circle can be calculated using the formula:

A = π * r²

For the first pipe:

r1 = 5.35 cm = 0.0535 m

A1 = π * (0.0535 m)² ≈ 0.00899 m²

For the second pipe:

r2 = 6.8 cm = 0.068 m

A2 = π * (0.068 m)² ≈ 0.01451 m²

Applying the Continuity Equation

Since the pressure is the same in both horizontal pipes, we can apply the continuity equation:

A1 * V1 = A2 * V2

We can express the volume flux (Q) as:

Q = A1 * V1 = A2 * V2

Finding the Volume Flux

To find the volume flux, we can rearrange the equation:

V1 = (A2 / A1) * V2

Substituting the areas we calculated:

V1 = (0.01451 m² / 0.00899 m²) * V2

V1 ≈ 1.613 * V2

Now, the volume flux can be expressed in terms of either velocity:

Q = A1 * V1 = A2 * V2

Using either expression, we can find the volume flux:

Q = A1 * V1 = 0.00899 m² * (1.613 * V2)

Q = 0.01451 m² * V2

Final Calculation

To find a specific numerical value for the volume flux, we would need the velocity of the fluid in either pipe. However, the relationship we derived shows how the volume flux is maintained despite the change in pipe diameter. If you know the velocity in one of the pipes, you can easily calculate the volume flux.

In summary, the volume flux remains constant across the two sections of the pipe, and you can find it using the areas and velocities of the fluid in each section. If you have any specific values for the velocities, we can plug them in to find the exact volume flux.

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