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A lift is moving down with acceleration a. A man in the lift drops a ball inside the lift. The acceleration of the ball as observed by the man in the lift and a man standing stationary on the ground are respectively- g , g g-a , g g-a, g-a a,g

A lift is moving down with acceleration a. A man in the lift drops a ball inside the lift. The acceleration of the ball  as observed by the man in the lift and a man standing stationary on the ground are respectively-
  1. g , g
  2. g-a , g
  3. g-a, g-a
  4. a,g

Grade:11

6 Answers

Runay
14 Points
8 years ago
a,g
Satviki Pathak
40 Points
8 years ago
How did you get that? Could you please let me know?
dara shannu
36 Points
8 years ago
g-a , g
Ball falls with an acceleration of ” g”. As the lift is moving with an acceleration of “a”
acceleration of ball w.r.t man =acceleration of ball – acceleration of man 
As in first case acceleration of man is ‘a’ answer becomes g-a
and in second case acceleration of man is 0 the answer becomes ‘g’
PRIYAL JAIN
21 Points
6 years ago
The answer would be G - A,G...................hhhhbfrfvergbiinnistgfghh2wejdkdikdocoewjdkdkenndndkekdnfkkdk
neeraj joshi
11 Points
5 years ago
2 option.
explanation-for a man in the lift concept of relativity is used ,therefore accceleration will be  = (g-a )
for person on the ground,   ma=mg implies a=g
ankit singh
askIITians Faculty 614 Points
3 years ago

Answer

 

Lift is accelerating downwards, so acceleration of lift w.r.t. ground  alg​=a
Acceleration of ball w.r.t. ground  abg​=g
Acceleration of ball w.r.t. lift   abl​=abg​−alg​=g−a

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