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Grade: 12th pass
        
A large tank is placed with water to height H. A small hole is made at base of tank it takes T1 time to decrease the height of water to H/n (n>1); it takes T2 time to take out rest of water. If T1=T2, then the value of n is
2 years ago

Answers : (2)

Kumari Sanjana
21 Points
							Let A1 be area of cross section of tank and  A2 be the area of cross section of hole When water level is x. Then -A1*dx= A2*v*dt-A1.dx=A2.√(2gx).dt(-A1/A2).(dx/√x)=√2g.dtIntegrating both sides-A1/A2.(2/3)((√x)^3=√(2g).tT1= (2A1/3A2.√2g)((√H)^3-(√H/n)^3)T2= (......................)((√H/n)^3)Now ,T1/T2&T1/T2=1 n=(4)^(1/3)
						
2 years ago
Kumari Sanjana
21 Points
							Let A1 be area of cross section of tank and A2 be the area of cross section of hole, When water level is x. Then -A1*dx= A2*v*dt-A1.dx=A2.√(2gx).dt(-A1/A2).(dx/√x)=√2g.dtIntegrating both sides-A1/A2.(2/3)((√x)^3=√(2g).tT1= (2A1/3A2.√2g)((√H)^3-(√H/n)^3)T2= (......................)((√H/n)^3)Now ,T1/T2&T1/T2=1 n=(4)^(1/3)
						
2 years ago
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