Mechanics

a large number of bullets are fired in all directions with same speed v. the maximum area on the ground on which these bullets will spread is

sakebm 34

12 Years agoGrade

4 Answers

Sunil Kumar FP

12 Years ago

maximum horizotal range of aprojectile is at angle of 45 degree.

range at this angle=v^2/g=radius of the cirrcle of maximum area

therefore area=pi v^4/g^2

thanks and regards

sunil kr

askIITian faculty

naveen

8 Years ago

πu square by g square is the answerWhere u is initial velocity g is acceleration due to gravityHai my name is Naveen samileti

Anumita Ghose

7 Years ago

Maximum Range, R = u² sin 2 (45)/g

=>R = v²/g

Now, Range becomes a the radius of the circular area in which the bullets are fired.

Area = πR² = π (v²/g)² => πv⁴/g²

With Regards,

Anumita Ghose

ankit singh

5 Years ago

XPLANATION:

The farthest the bullet lands will be the bullets which are launched at an angle of 45^{\circ}. And the farthest they will go will be v^{2} / g. So the radius of the circle which the bullets cover is v^{2} / g.

Hence the area is P I \times R^{2}. So the area is\mathrm{P} I \times \mathrm{v}^{4} / \mathrm{g}^{2}.

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a large number of bullets are fired in all directions with same speed v. the maximum area on the ground on which these bullets will spread is

sakebm 34

4 Answers

Sunil Kumar FP

naveen

Anumita Ghose

ankit singh

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