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A juggler throws balls into air . He throws one whenever the previous one is at the heighest point how high do the balls rise if he throws ‘n’ balls each second? A projectile is fired from the ground with an velocity10m/s making an angle 60 with horizontal .how will be the path visibleto two observers, sitting in two buses moving with same speed along the same road in opposite direction,when speed of buses is [a] 10m/s [b] 5m/s [c] 2m/s

```
2 years ago

Arun
25333 Points
```							Juggler throws the ball into the air with ball having  initial velocity = uAt the highest point of its path velocity will be zero as at maximum height velocity =0So final velocity=0According to question juggler throws a ball each second so for "n" balls time taken to reach highest position (t)= 1/n     v=u+gt     0=u-g/n    -u=-g/n    u=g/nS= ut-gt²/2S=u/n-g/2n²But u=g/nS= g/n²-g/2n²S=g/2n²
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions