Flag Mechanics> (a) If the maximum acceleration that is t...
question mark

(a) If the maximum acceleration that is tolerable for passengers in a subway train is 1.34 m/s2 and subway stations are located 806 m apart, what is the maximum speed a subway train can attain between stations? (b) What is the travel time between stations? (c) If a subway train stops for 20 s at each station, what is the maximum average speed of the train, from one start-up to the next? (d) Graph x, v, and a versust for the interval from one start-up to the next.

Vaidehi , 8 Years ago
Grade 12th pass
anser 1 Answers
Arun
a) Distance available to accelerate = (806/2) = 403m. 
Velocity = sqrt. (2ad), = sqrt. (2.68 x 403), = 32.86m/sec. Speed max = 118.31 kph. 
b) Time to accelerate = (v/a), = 32.86/1.34, = 24.52 s. Doube it, = 49.04s. 
c) (49.04+ 20) = 69.04 s. 
In 69.04 s., it has travelled 806m. 
(806/69.04 ) = 11.67 m/sec average. Speed average = (11.67 x 3600/1000) = 42.012 kph.
Last Activity: 8 Years ago
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments