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`        A hollow cylinder with inner radius R, outer radius 2R and mass M is rolling with speed of its axis v.what is its kinetic energy? `
one year ago

Eshan
2095 Points
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one year ago
Abhimanyu singh
15 Points
```							Well the above answer is wrong the moment of inertia will be 1/2m(r1^2 + r2^2)         where  r1=r , r2=2r So MOI is 5/2mr^2
```
one year ago
Shubham Singh
15 Points
```							Since it's a hollow sphere so rings moment of inertia will be considered so moi is m[r1^2+r2^2] Now r1=R and r2=2R put these values in kinetic energy formula
```
6 months ago
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Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions