A frictionless wire AB is fixed on a sphere of radius R. A very small spherical ball slips on this wire. The time taken by this ball to slip from A to B is?

Question

Arun · Answer

Dear student

time taken by this ball to slip from A to B is:

AB = R/(cos theta) theta = 45^o

AB = √2 R = 2R/√2 = 2R cos?

2R cos? = 1/2x gcos? x t²

t = 2 √R/g
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Arun (askIITians forum expert)

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A frictionless wire AB is fixed on a sphere of radius R. A very small spherical ball slips on this wire. The time taken by this ball to slip from A to B is?

A frictionless wire AB is fixed on a sphere of radius R. A very small spherical ball slips on this wire. The time taken by this ball to slip from A to B is?

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A frictionless wire AB is fixed on a sphere of radius R. A very small spherical ball slips on this wire. The time taken by this ball to slip from A to B is?

A frictionless wire AB is fixed on a sphere of radius R. A very small spherical ball slips on this wire. The time taken by this ball to slip from A to B is?

1 Answers

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