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A freely falling particle aquries a velocity Vms^-1 after falling for n sec from rest at t=0.the height through which it falls from time t=(n-2)s and t=n s in meter is A) v/2(1-1/n)B)v(1-1/2n)C)2v(1-1/n)D)2v(1-1/2n)

Sri laasya , 6 Years ago
Grade 11
anser 1 Answers
Karan Gupta

Last Activity: 6 Years ago

V = gn
U = g(n-2)
V^2 – U^2 = 2gH
Means (gn)^2 – [g(n-2)]^2 = 2gH
4g(n-1) = 2H
H = 2g(n-1) = 2gn(n-1)/n = 2V(1-1/n)
Hence Answer: Option C

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