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A freely falling body travels how much %in its 5th set?
A freely falling body travels how much %in its 5th set?

```
2 years ago

Arun
25768 Points
```							As you need to find the distance covered in fifth second, you should find the distance covered in six seconds and five seconds and subtract them.As per the equation s=ut+1/2(at^2)u=0, a=g (acceleration due to gravity) and t = timeDistance covered in 6 seconds (let’s call it s6)= 1/2 (36g)Distance covered in 5 seconds (let’s call it s5)= 1/2 (25g)therefore answer is s6-s5= 11g/2 (put value of g as 10 or 9.8 as per you accuracy requirements and solve to get answer).
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions