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        A freely falling body from a tower of height h covers a distance h/2 in the last second of its motion. The height of the tower is nearly1]58m2]50m3]60m4]55m
2 years ago

Piyush Kumar Behera
419 Points
							see in this type of problems use the following approach...we alreaady know that =  S = U + a/2(2N-1) [ WHERE U = INITIAL SPEED , & N = value of TIME IN Tth SECOND . ]so using the formula ------h/2 = u + a/2(2t-1)h/10 = 2t-1 { u=0 & a=10}t = h+10/20so, total time = h+10/20now by formula = h=ut + 1/2at^2, (u=0 a=10)h=h^2+100+20h/80on solving - h = 58.28 metres.if you are really helped then please approve

2 years ago
Manoj Dixit
29 Points
							let h distance be covered in t seconds then h/2 distance is covered in t-1 secondsfirst using the formula of distance covered in nth second we geth/2 = 0 + 10/2(2t-1)     { u=0 a=10 }on solving this we get h = 20t-10     equation 1we know s = ut + at2/2here u = 0 a = 10 s = hh = 5t2   puttting this in equation 1 we get 5t2 = 20t -10t2 – 4t + 2on solving this equation we get t = 2 $\displaystyle \displaystyle \pm$ 21/2 we will choose 2 - 2½the answer would be very small hence according to the options we will choose               t = 2 + 21/2we have already seen that h= 5t2putting the value of t we get h = 30 + 20*2½putting 21/2 = 1.4 we get h = 30 + 28 = 58 hence the answer is 58please approve

2 years ago
Ankit Jaiswal
165 Points
							Hi Hermonie,                     I think this might helplet h distance be covered in t seconds then h/2 distance is covered in t-1 secondsfirst using the formula of distance covered in nth second we geth/2 = 0 + 10/2(2t-1)     { u=0 a=10 }on solving this we get h = 20t-10     equation 1we know s = ut + at2/2here u = 0 a = 10 s = hh = 5t2   puttting this in equation 1 we get 5t2 = 20t -10t2 – 4t + 2on solving this equation we get t = 2 $\displaystyle \displaystyle \pm$ 21/2 we will choose 2 - 2½the answer would be very small hence according to the options we will choose               t = 2 + 21/2we have already seen that h= 5t2putting the value of t we get h = 30 + 20*2½putting 21/2 = 1.4 we get h = 30 + 28 = 58 hence the answer is 58please approve and any doubt freely

2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions