Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
A force F = -K (y (where K is a positive constant) acts on a particle moving in the xy plane. Starting from the origin, the particle is taken along the positive x axis to the point (a, 0), and then parallel to the y axis to the point (a, a), The total work done by the force F on the particle is a) –Ka2 b) 2Ka2 c) – Ka2 d) Ka2
Your question isnt visible.please post it again. Though ill tell you now how to proceed. I assumeF = -ky jPath 1 :Y= 0So work done =0Path 2 :Work done = -F.dy=integration of Kydy from 0 to aAnswer = ka^2/2ThanksBharat BajajAskiitians faculty
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -