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A force F = -K (y (where K is a positive constant) acts on a particle moving in the xy plane. Starting from the origin, the particle is taken along the positive x axis to the point (a, 0), and then parallel to the y axis to the point (a, a), The total work done by the force F on the particle isa) –Ka2b) 2Ka2c) – Ka2d) Ka2
Your question isnt visible.please post it again. Though ill tell you now how to proceed. I assumeF = -ky jPath 1 :Y= 0So work done =0Path 2 :Work done = -F.dy=integration of Kydy from 0 to aAnswer = ka^2/2ThanksBharat BajajAskiitians faculty
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