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A force F = -K (y (where K is a positive constant) acts on a particle moving in the xy plane. Starting from the origin, the particle is taken along the positive x axis to the point (a, 0), and then parallel to the y axis to the point (a, a), The total work done by the force F on the particle is a) –Ka2 b) 2Ka2 c) – Ka2 d) Ka2

 A force F = -K (y (where K is a positive constant) acts on a particle moving in the xy plane. Starting from the origin, the particle is taken along the positive x axis to the point (a, 0), and then parallel to the y axis to the point (a, a), The total work done by the force F on the particle is
a) –Ka2
b) 2Ka2
c) – Ka2
d) Ka2

Grade:12th pass

1 Answers

bharat bajaj IIT Delhi
askIITians Faculty 122 Points
9 years ago
Your question isnt visible.please post it again. Though ill tell you now how to proceed. I assume
F = -ky j

Path 1 :
Y= 0
So work done =0

Path 2 :
Work done = -F.dy
=integration of Kydy from 0 to a
Answer = ka^2/2

Thanks
Bharat Bajaj
Askiitians faculty

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