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A force F = (3xi + 4j ) Newton (where x is in metres) acts on a particle which moves from a position (2m, 3m) to (3m, 0m). Then the work done is
Given Force,F =3 i^ +4 y^ Displacement of the particle, from given coordinates :Δ r = r f − r i =(3 i^ +0 j^ )−(2 i^ +3 j^ )⇒Δ r =( i^ −3 j^ )mSo, work done by forcew= F .A r =(3 i^ +4 j^ ).( i^ −3 j^ )⇒w=−9 j^
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