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Grade: 11
        
A force acts for 10s on a body of man 10kg initially at rest ,after which the force ceases to act. if the body traversed 0.5m in the next 5s then find F.
2 years ago

Answers : (1)

DR STRANGE
212 Points
							
HI Sai,
let the force be F,
F=Ma
a=F/M=F/10
NOW, v=u+at, v= 0+(F/10)*10=F (u=0, initially at rest)
now, v=s/t.
it traversed 0.5m in next 5s
v=F=0.5/5=0.1N............ANS
Plz approve if you are satisfied :)
2 years ago
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