Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A football player punts the football so that it will have a "hang time" (time of flight) of 4.50 s and land 50 yd (= 45.7 m) away. If the ball leaves the player's foot 5.0 ft (= 1.52 m) above the ground, what is its initial velocity (magnitude and direction)?

A football player punts the football so that it will have a "hang time" (time of flight) of 4.50 s and land 50 yd (= 45.7 m) away. If the ball leaves the player's foot 5.0 ft (= 1.52 m) above the ground, what is its initial velocity (magnitude and direction)?

Grade:11

1 Answers

Kevin Nash
askIITians Faculty 332 Points
6 years ago
234-161_1.PNG
Therefore, the horizontal component of initial velocity of the football is 10.2 m/s.
234-1098_1.PNG
Therefore, the vertical component of initial velocity of the football is 22.1 m/s.
234-1360_1.PNG
Therefore the magnitude of initial velocity of the football is 24.3 m/s.

234-747_1.PNG
Therefore, the angle between the initial velocity vector of football and the horizontal is 65.2°.

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free