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A football player punts the football so that it will have a "hang time" (time of flight) of 4.50 s and land 50 yd (= 45.7 m) away. If the ball leaves the player's foot 5.0 ft (= 1.52 m) above the ground, what is its initial velocity (magnitude and direction)?

A football player punts the football so that it will have a "hang time" (time of flight) of 4.50 s and land 50 yd (= 45.7 m) away. If the ball leaves the player's foot 5.0 ft (= 1.52 m) above the ground, what is its initial velocity (magnitude and direction)?

Grade:11

1 Answers

Kevin Nash
askIITians Faculty 332 Points
8 years ago
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Therefore, the horizontal component of initial velocity of the football is 10.2 m/s.
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Therefore, the vertical component of initial velocity of the football is 22.1 m/s.
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Therefore the magnitude of initial velocity of the football is 24.3 m/s.

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Therefore, the angle between the initial velocity vector of football and the horizontal is 65.2°.

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