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# A firecracker is thrown with velocity of 30m/s in a direction which makes an angle of 75` with vertical axis. At some point on its trajectory, the firecracker splits into 2 identical pieces in such a way that one piece falls 27m far from shooting point. Assuming that all trajectories are contained in same plane, how far will other piece fall from the shooting point? (g=10m/s2 , air resistance neglected)

Shobhit Varshney IIT Roorkee
7 years ago
Hi,

the range of the projecitle if it hasn’t exploded,
R = (u2sin2)/g
Since, no external force was there, so COM will be moving on the original trajectory.
When the parts are about to hit the ground, (origin is the point of shooting)
m *R = (m/2) * 27 + (m/2) * x

Find x from the above equation.

thanks,.