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A firecracker is thrown with velocity 30m/s in a dir which makes an angle of 75°with the vertices axis . At some pt in trajectory the firecracker splits into two identical pieces in such a way that one piece  falls 27m away from shooting pt. Assuming that all trajectories are contained in same plane how far will the other piece fall away from shooting pt???
one year ago

Answers : (1)

Arun
23368 Points
							
)/gSince, no external force was there, so COM will be moving on the original trajectory.When the parts are about to hit the ground, (origin is the point of shooting)m *R = (m/2) * 27 + (m/2) * xFind x from the above equation.\Thetasin22the range of the projecitle if it hasn’t exploded,R = (u
Regards Arun
one year ago
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