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A firecracker is thrown with velocity 30m/s in a dir which makes an angle of 75°with the vertices axis . At some pt in trajectory the firecracker splits into two identical pieces in such a way that one piece falls 27m away from shooting pt. Assuming that all trajectories are contained in same plane how far will the other piece fall away from shooting pt???

A firecracker is thrown with velocity 30m/s in a dir which makes an angle of 75°with the vertices axis . At some pt in trajectory the firecracker splits into two identical pieces in such a way that one piece  falls 27m away from shooting pt. Assuming that all trajectories are contained in same plane how far will the other piece fall away from shooting pt???

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1 Answers

Arun
25750 Points
5 years ago
)/gSince, no external force was there, so COM will be moving on the original trajectory.When the parts are about to hit the ground, (origin is the point of shooting)m *R = (m/2) * 27 + (m/2) * xFind x from the above equation.\Thetasin22the range of the projecitle if it hasn’t exploded,R = (u
Regards Arun

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