Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
        a fan is running at 3000 rpm. It is switched off.It comes to rest by uniformly decreasing its angular speed in 10 seconds.The total number of revolution in this period.
2 years ago

Arun
24497 Points
							Dear Aadesh thanks= 500 - 250 = 250 rotations.2= 50* 10 + 0.5 (-5) 10So,2tt+ 0.5o = wNow,2= – 5 rotations / st,+oSo, w = 0 = wtime = 10 seconds= 300 rpm = 3000 /60 rotations per second = 50 rpsoGiven , wHi, RegardsArun (askIITians forum expert)

2 years ago
Arun
24497 Points
							thanks= 250 rotations.2= 50* 10 + 0.5 (-5) 10So,2tt+ 0.5o = wNow,2= – 5 rotations / st,+oSo, w = 0 = wtime = 10 seconds= 3000 rpm = 50 rotations per secondoGiven , wHi,

2 years ago
Mohit Jaiswal
15 Points
							3000/6=50 rps . wf=wi+ (alpha)t 0=50+(alpha)10-alpla×10=50Alpha=-5S=ut+1/2at^2S=50×10 +1/2×-5×10×10S=500-250S=250So answer is 250 revolutions

one year ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions

Post Question