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        a fan is running at 3000 rpm. It is switched off.It comes to rest by uniformly decreasing its angular speed in 10 seconds.The total number of revolution in this period.
one year ago

Arun
22545 Points
							Dear Aadesh thanks= 500 - 250 = 250 rotations.2= 50* 10 + 0.5 (-5) 10So,2tt+ 0.5o = wNow,2= – 5 rotations / st,+oSo, w = 0 = wtime = 10 seconds= 300 rpm = 3000 /60 rotations per second = 50 rpsoGiven , wHi, RegardsArun (askIITians forum expert)

one year ago
Arun
22545 Points
							thanks= 250 rotations.2= 50* 10 + 0.5 (-5) 10So,2tt+ 0.5o = wNow,2= – 5 rotations / st,+oSo, w = 0 = wtime = 10 seconds= 3000 rpm = 50 rotations per secondoGiven , wHi,

one year ago
Mohit Jaiswal
15 Points
							3000/6=50 rps . wf=wi+ (alpha)t 0=50+(alpha)10-alpla×10=50Alpha=-5S=ut+1/2at^2S=50×10 +1/2×-5×10×10S=500-250S=250So answer is 250 revolutions

9 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions