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A dog of mass 5kg is resting on a flat boat of mass 20kg . Such that it is 10m from the shore .Boat is resting on frictionlesswater . The dog walks 4m through the boat towards the shore and finally halts .find the final separation between dog and shore

mansu susan joji , 8 Years ago
Grade 10
anser 1 Answers
Manas Shukla

Last Activity: 8 Years ago

The centre of mass for the system wont change.
So
0 = mass of dog x distance moved by dog + mass of boat x distance moved by boat
So we find
Distance moved by the boat = -1
Thus it will be further away from shore by 1m
Total distance = 11m

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