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A disc of radius R , mass M lies on smooth horizontal surface. Two persons of equal mass m standing on diametrically opposite points. Both persons start moving in same sense, then find angle rotated by disc when both persons complete round trip?
In same sense as it has been mentioned in the qstn. assuming both v speed as clockwise (let),the disc to be assumed as a rectangular piece of length 2*pi*R and width R (ct from the first person standing)then from, m1 x1 = m2 x2 we get,M * x = m * (2*pi*R – x)x = 2M*PI*R/(M+m)This is due to one person.Due to two persons the total angle would be=>x = 4M*PI*R/(M+m)
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