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A dart is thrown horizontally with an initial speed of 19 m/s toward point P , the bull's-eye on a dart board. It hits at point Q on the rim, vertically below P , 0.19 s later. (a) What is the distance PQ ? (b) How far away from the dart board is the dart released?

A dart is thrown horizontally with an initial speed of  19 m/s  toward point P, the bull's-eye on a dart board. It hits at point Q on the rim, vertically below P 0.19 s  later. (a) What is the distance PQ(b) How far away from the dart board is the dart released?

Grade:12

2 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
4 years ago
Dear student

PQ = 0.5 gt*t
= 0.1805 m

Distance between dart board and thrower = u*t = 3.61 m

Regards
Arun
25750 Points
4 years ago
Dear student
 
Please attach an image of question. As it is required to know the position of P and Q.
I will be happy to help you.
 
Regards

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