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`        A dart is thrown horizontally with an initial speed of  19 m/s  toward point P, the bull's-eye on a dart board. It hits at point Q on the rim, vertically below P,  0.19 s  later. (a) What is the distance PQ? (b) How far away from the dart board is the dart released?`
4 months ago

Saurabh Koranglekar
3431 Points
```							Dear studentPQ = 0.5 gt*t= 0.1805 mDistance between dart board and thrower = u*t = 3.61 mRegards
```
4 months ago
Arun
23492 Points
```							Dear student Please attach an image of question. As it is required to know the position of P and Q.I will be happy to help you. Regards
```
4 months ago
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### Course Features

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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions