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Grade 12th passMechanics

a cylinder contains 0.45 m cube of gas at 1*105 n/m2.determine 1)the mass of gas 2)the value of index,,n for compression.the increase in internal energy of the gas and 4)the heat received or rejected by the gas during compression.take gamma=1.4R.

Profile image of ravi kumar singh
9 Years agoGrade 12th pass
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1 Answer

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ApprovedApproved Tutor Answer1 Year ago

To tackle this problem, we need to break it down into manageable parts. We have a cylinder containing gas, and we need to find the mass of the gas, the value of the index for compression, the increase in internal energy, and the heat exchanged during the compression process. Let's go through each part step by step.

1. Calculating the Mass of the Gas

The mass of the gas can be determined using the ideal gas law, which is expressed as:

PV = nRT

Where:

  • P = pressure (in pascals)
  • V = volume (in cubic meters)
  • n = number of moles of gas
  • R = ideal gas constant (approximately 8.314 J/(mol·K))
  • T = temperature (in kelvins)

To find the mass, we first need to express the number of moles (n) in terms of mass (m) and molar mass (M):

n = m / M

Substituting this into the ideal gas law gives:

PV = (m/M)RT

Rearranging for mass:

m = (PVM) / (RT)

However, we need the temperature to proceed. If we assume the gas behaves ideally and we know the molar mass, we can calculate the mass once we have the temperature.

2. Finding the Value of the Index (n) for Compression

The index of compression (n) is related to the specific heat capacities of the gas. For an ideal gas, the relationship is given by:

n = Cv / Cp

Where:

  • Cv = specific heat at constant volume
  • Cp = specific heat at constant pressure

For a diatomic gas, the ratio of specific heats (γ) is given as:

γ = Cp / Cv

Given that γ = 1.4, we can express:

Cp = 1.4 * Cv

Using the relationship between n and γ, we find:

n = 1 / (γ - 1) = 1 / (1.4 - 1) = 2.5

3. Increase in Internal Energy of the Gas

The change in internal energy (ΔU) for an ideal gas can be calculated using the formula:

ΔU = nCvΔT

To find ΔT, we need to know the initial and final temperatures, which we can derive from the pressure and volume if we assume an isothermal or adiabatic process. For simplicity, let's assume an adiabatic process where:

ΔU = (P1V1 - P2V2)

Without specific values for P2 and V2, we cannot compute ΔU directly. However, if we assume the gas is compressed to a certain volume, we can calculate the change in internal energy based on the work done during compression.

4. Heat Received or Rejected by the Gas During Compression

The heat exchanged (Q) during the compression can be determined using the first law of thermodynamics:

ΔU = Q - W

Where W is the work done on the gas. For an adiabatic process, we can express:

Q = ΔU + W

Work done on the gas during compression can be calculated as:

W = ∫ P dV

Again, without specific values for the final pressure and volume, we cannot compute W directly. However, if we assume a certain compression ratio, we can estimate the work done and subsequently the heat exchanged.

In summary, while we can set up the equations and relationships needed to solve this problem, specific values for temperature and final pressure/volume are necessary to compute numerical answers. If you have those values, we can plug them into the equations to find the mass, internal energy change, and heat exchanged during the compression process.