Question icon
Grade 12th passMechanics

a cyclist moving at a speed of 17.64km/hr describes a circle of radius 9.8 m.if the cyclist is held in balance ,the cofficient of friction between the tyre and the ground is

Profile image of MISHIKA PARASHAR
12 Years agoGrade 12th pass
Answers icon

1 Answer

Profile image of Vasantha Kumari
12 Years ago

Given speed is such that it balances the force of friction, hence

Maximum speed vmax = vmgr

Or v2max = mgr

v2max / gr = m

substituting the values, we have

v2max / gr = m

vmax = 17.64 km/hr = 17.6 x 5/18 =4.87

v2max / gr = m

(4.87)2 / 9.8 x 9.8 =m

23.7169/ 96.04

Thus, the cofficient of friction between the tyre and the ground is m = 0.2469

Thanks & Regards,

Vasantha Sivaraj,

askIITians faculty