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Grade: 12

                        

A cubicle block of wood of edge 0.2m weighing 6.4kgf floats on water. Find the depth of immersion. Given, density of water 1000kg per cubic metre. Show working out please.

8 months ago

Answers : (2)

Arun
24742 Points
							
s = 30 cm = 0.3 m
m = 21.6 kg
# Solution-
Let h be depth of immersion and Vi bs volume of immersed part.
Here, liquid displaced is equal to weight of wooden block.
mg = Vi.ρ0.g
m = s×s×h.ρ0
6.4 = 0.2^2 × 1000 × h
h = 0.16 m
h = 16 cm
 
8 months ago
Vikas TU
12278 Points
							
Dear student 
30 × 30 × 10^-4 × h × g = 21.6
Let h = the depth of immersion then
H= 24
Good Luck 
Cheers 
8 months ago
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