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`        a cubical boxis to be constructed with iron sheets of 1mm thickness.what can be the the minimum value of external edge so thatcube doesnt sink in water.density of iron=8000.density of water=1000     `
2 months ago

```							 Let the length of the side of the cube be 'l' meters Volume of the cube = L³ The area of each face of the cube is L² Considering all the 6 faces of the cube, the weight of the cube is  = 6 × L² × 8000 kg/m³ × 0.001 m  =  L² × 48 kg/m² Weight of the water displaced by the volume of the cube =  L³ × 1000 kg/m³ Condtion for the block not to sink in water is Weight of the cube = Weight of the water displaced by the volume of the cube L² × 48 kg/m² = L³ × 1000 kg/m³ On solving we getL =  48 kg/m² / 1000 kg/m³ L = 0.048 m L = 48 mm
```
2 months ago
```							Dear student Total surface area of the cube = 6a²The volume of the iron in the box = 6a² ×  1 × 10⁻³ = 6 × 10⁻³ a² m³Now, The mass of iron in the box = Volume × density=  6 × 10⁻³ a² × 8000=48a² kgWeight = 48 × 10 = 480 N.The volume of the water displaced = a³ cm³  [It will be equal to volume of cube displaced].∴ Upthrust = a³ × 1000 × 10= 10⁴a³Now, 10⁴a³ = 480a = 48 × 10⁻³ m.Therefore, a = 4.8 cm.
```
2 months ago
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