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A cubical block of wood of edge 0.2 m weighing 6.4 kgf floats on water . Find the depth of immersion . Given density of water 1000kg/m3. Ans:1.57m
Water density is 1000 kg/m^3 so 0.2m x 0.2 m x D * 1000 kg/m^3 = 6.4 kgf, where D is depth of immersion. Solve for D D = 6.4kg/(1000x 0.2x 0.2) = 0.16 m
A cubical block of wood of edge 0.2m weight 6.4kgf floats on water. Find the depth of immersion. Given, density of water 1000kg m-3
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