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`        A cube of wood supporting a 200gm mass just float in water.when the mass is removed the cube rises by 2cm at equilibrium. Find side of the cube`
2 years ago

Arun
23325 Points
```							Dear student

Let the edge of cube be l. When mass is on the cube of wood
200 g + l3 d wood g = l3 dwater g
⇒ l3 dwood = l3 dwater – 200 … (i)
When the mass is removed
l3 dwood = (l - 2 ) l2 dwater … (ii)
From (i) and (ii)
l3 dwater - 200 = (l- 2) l2 dwater
But dwater = 1
∴ l3 - 200 = l2 (l - 2)
⇒ l = 10 cm

Regards

```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions