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A cube of wood supporting 200gm mass just floats in water. When the mass is removed, the cube ruses by 2cm. What is the size of the cube?
Let the edge of cube be l. When mass is on the cube of wood 200g + l3dwoodg = l 3waterg ? l3dwood = l 3water – 200 …..(i) When the mass is removed l3dwood = (l-2) l2dwater …..(ii) From (i) and (ii) l3dwater – 200 = (l-2) l2dwater But dwater = 1 ? l3 – 200 = l2 (l-2) ? l = 10cm
Let the edge of cube be l. When mass is on the cube of wood
200g + l3dwoodg = l 3waterg
? l3dwood = l 3water – 200 …..(i)
When the mass is removed
l3dwood = (l-2) l2dwater …..(ii)
From (i) and (ii)
l3dwater – 200 = (l-2) l2dwater
But dwater = 1
? l3 – 200 = l2 (l-2)
? l = 10cm
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