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A CRICKETER CAN THROW A BALL TO MAXIMUM HORIZONTAL DISTANCE OF 100m WITH SAME SPEED ,HOW MUCH HIGH ABOVE THE GROUND CAN THROW THE SAME BALL

```
3 years ago

Arun
25768 Points
```							We know that horizontal range is maximum if the angle of projection is 45o and is given byRmax = u2 / gHere, Rmax = 100 mso, u2 / g  = 100 mIf the cricketer throws the ball vertically upwardthen the ball will attain the maximum height from the groundHmax = u2 / 2g  = 100 /2 = 50 m.
```
3 years ago
Rishi Sharma
628 Points
```							Dear Student,Please find below the solution to your problem.We know that horizontal range is maximum if the angle of projection is 45oand is given byRmax= u2/ gHere, Rmax= 100 mso, u2/ g = 100 mIf the cricketer throws the ball vertically upwardthen the ball will attain the maximum height from the groundHmax= u2/ 2g= 100 /2= 50 m.Thanks and Regards
```
6 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions