A CRICKETER CAN THROW A BALL TO MAXIMUM HORIZONTAL DISTANCE OF 100m WITH SAME SPEED ,HOW MUCH HIGH ABOVE THE GROUND CAN THROW THE SAME BALL

Dear Student,
Please find below the solution to your problem.

We know that horizontal range is maximum if the angle of projection is 45oand is given by
Rmax= u2/ g
Here, Rmax= 100 m
so, u2/ g = 100 m
If the cricketer throws the ball vertically upwardthen the ball will attain the maximum height from the ground
Hmax= u2/ 2g
= 100 /2
= 50 m.

Thanks and Regards