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A cricket ball thrown from a height of 1.8m at an angle of 30°with the horizontal at a speed of 18m/s is caught by another fields man at a height of 0.6m from the ground. How far were the two men apart?

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Profile image of Teddy
9 Years agoGrade 12
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1 Answer

Profile image of Arun
6 Years ago
Dear Student,
Vx= 18cos 30= 9root3
Vy=18sin30=9
 
h=1.2
=>1.2= Vyt-gt^2/2
=>1.2=9t-5t^2
=>25t^2-45t+6=0
=>t=1.65 or 0.146.