Create your Smart Home App in the Free Webinar on Home Automation. Register Now
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Free webinar on App Development Learn to create your own Smart Home App
16th Jan @ 5:00PM for Grade 1 to 10
Sit and relax as our customer representative will contact you within 1 business day
A cord is used to lower vertically a block of mass M a distance d at a constant downward acceleration of g/4. (a) Find the work done by the cord on the block. (b) Find the work done by the force of gravity.
Check the net force on the object and then write the equation of motion.Tension and gravity are working on the object and motion is in direction of gravity. Hence the equation of motion is,Mg-T= ma. -(1)As the acceleration of the object is given as he as the acceleration of the object is given as G divided g divided by 4.T=3mg/4(A) work done =force×displacementAs we know that displacement is in opposite direction of force.Hence workdone is (-ve).W=-f.dW=-(3/4)×Mg×d(B) now work done by gravity is in direction of displacement hence it is positive.W=force(of gravity)×displacement W=Mgd
Dear student,Please find the solution to your problem. We have,T – Mg = MaT = Mg + M( – g/4) = ¾ MgHence, work done by tension, WT = T.(–d) = – Td = – ¾ Mgd The work done by Gravity, Wg = Fg.(d) = Mgd Thanks and regards,Kushagra
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -