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A constant power P is acting on a car of mass m . The velocity increases from v 1 and v 2 .The distancce travelled by the car during this change is a,3p/m(v 2 2 -v 1 2 ) b,m/3p(v 2 -v 1 ) c,m/3p(v 2 2 -v 1 2 ) d,m/3p(v 2 3 -v 1 3 )
A constant power P is acting on a car of mass m . The velocity increases from v1 and v2 .The distancce travelled by the car during this change is a,3p/m(v22-v12)b,m/3p(v2-v1)c,m/3p(v22-v12)d,m/3p(v23-v13)

```
4 years ago

Vikas TU
14149 Points
```							Since Power is constant,P = F x V => MaV and also,a = vdv/dxputting value of a in Power we get,(P/m)dx = v^2dvIntegerating both sides we get,Px/m = (v2^3 – v1^3)/3x = (v2^3 – v1^3)m/3p
```
4 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions